2*x^2+4^2=5x^2+4^2

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Solution for 2*x^2+4^2=5x^2+4^2 equation: 



2x^2+4^2=5x^2+4^2

We move all terms to the left:

2x^2+4^2-(5x^2+4^2)=0

We add all the numbers together, and all the variables

2x^2-(5x^2+4^2)+16=0

We get rid of parentheses

2x^2-5x^2+16-4^2=0

We add all the numbers together, and all the variables

-3x^2=0

a = -3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-3)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-6}=0$

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